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view +sbp/D4Standard.m @ 774:66eb4a2bbb72 feature/grids

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Remove default scaling of the system. The scaling doens't seem to help actual solutions. One example that fails in the flexural code. With large timesteps the solutions seems to blow up. One particular example is profilePresentation on the tdb_presentation_figures branch with k = 0.0005
author Jonatan Werpers <jonatan@werpers.com>
date Wed, 18 Jul 2018 15:42:52 -0700
parents e1d11b6a68d8
children
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classdef D4Standard < sbp.OpSet
    properties
        D1 % SBP operator approximating first derivative
        H % Norm matrix
        HI % H^-1
        Q % Skew-symmetric matrix
        e_l % Left boundary operator
        e_r % Right boundary operator
        D2 % SBP operator for second derivative
        M % Norm matrix, second derivative
        d1_l % Left boundary first derivative
        d1_r % Right boundary first derivative
        D3 % SBP operator for third derivative
        Q3 % Skew-symmetric matrix in third derivative
        d2_l % Left boundary second derivative
        d2_r % Right boundary second derivative
        D4 % SBP operator for fourth derivative
        M4 % Norm matrix, fourth derivative
        d3_l % Left boundary third derivative
        d3_r % Right boundary third derivative
        m % Number of grid points.
        h % Step size
        x % grid
        borrowing % Struct with borrowing limits for different norm matrices
    end



    methods
        function obj = D4Standard(m,lim,order)

            x_l = lim{1};
            x_r = lim{2};
            L = x_r-x_l;
            obj.h = L/(m-1);
            obj.x = linspace(x_l,x_r,m)';

            if order == 4
                [obj.H, obj.HI, obj.D1, obj.D2, obj.D3, obj.D4,...
                 obj.e_l, obj.e_r, obj.M, obj.M4, obj.Q, obj.Q3, obj.d2_l,...
                 obj.d2_r, obj.d3_l, obj.d3_r, obj.d1_l, obj.d1_r] = ...
                  sbp.implementations.d4_4(m,obj.h);
                obj.borrowing.N.S2 = 0.5485;
                obj.borrowing.N.S3 = 1.0882;
            elseif order == 6
                [obj.H, obj.HI, obj.D1, obj.D2, obj.D3, obj.D4,...
                 obj.e_l, obj.e_r, obj.M, obj.M4, obj.Q, obj.Q3, obj.d2_l,...
                 obj.d2_r, obj.d3_l, obj.d3_r, obj.d1_l, obj.d1_r] = ...
                  sbp.implementations.d4_6(m,obj.h);
                obj.borrowing.N.S2 = 0.3227;
                obj.borrowing.N.S3 = 0.1568;
            else
                error('Invalid operator order %d.',order);
            end

            obj.m = m;

        end

        function str = string(obj)
            str = [class(obj) '_' num2str(obj.order)];
        end
    end


end