Mercurial > repos > public > sbplib
view +sbp/+implementations/d4_variable_2.m @ 774:66eb4a2bbb72 feature/grids
Remove default scaling of the system.
The scaling doens't seem to help actual solutions. One example that fails in the flexural code.
With large timesteps the solutions seems to blow up. One particular example is profilePresentation
on the tdb_presentation_figures branch with k = 0.0005
author | Jonatan Werpers <jonatan@werpers.com> |
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date | Wed, 18 Jul 2018 15:42:52 -0700 |
parents | 43d02533bea3 |
children |
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% Returns D2 as a function handle function [H, HI, D1, D2, D4, e_l, e_r, M4, d2_l, d2_r, d3_l, d3_r, d1_l, d1_r] = d4_variable_2(m,h) %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%% 4:de ordn. SBP Finita differens %%% %%% operatorer framtagna av Ken Mattsson %%% %%% %%% %%% 6 randpunkter, diagonal norm %%% %%% %%% %%% Datum: 2013-11-11 %%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% BP = 2; if(m < 2*BP) error('Operator requires at least %d grid points', 2*BP); end % Norm Hv = ones(m,1); Hv(1) = 1/2; Hv(m) = 1/2; Hv = h*Hv; H = spdiag(Hv, 0); HI = spdiag(1./Hv, 0); % Boundary operators e_l = sparse(m,1); e_l(1) = 1; e_r = rot90(e_l, 2); d1_l = sparse(m,1); d1_l(1:3) = 1/h*[-3/2 2 -1/2]; d1_r = -rot90(d1_l, 2); d2_l = sparse(m,1); d2_l(1:3) = 1/h^2*[1 -2 1]; d2_r = rot90(d2_l, 2); d3_l = sparse(m,1); d3_l(1:4) = 1/h^3*[-1 3 -3 1]; d3_r = -rot90(d3_l, 2); % First derivative SBP operator, 1st order accurate at first 6 boundary points stencil = [-1/2, 0, 1/2]; diags = [-1 0 1]; Q = stripeMatrix(stencil, diags, m); D1 = HI*(Q - 1/2*e_l*e_l' + 1/2*e_r*e_r'); % Second derivative, 1st order accurate at first boundary points M = sparse(m,m); scheme_width = 3; scheme_radius = (scheme_width-1)/2; r = (1+scheme_radius):(m-scheme_radius); function D2 = D2_fun(c) Mm1 = -c(r-1)/2 - c(r)/2; M0 = c(r-1)/2 + c(r) + c(r+1)/2; Mp1 = -c(r)/2 - c(r+1)/2; M(r,:) = spdiags([Mm1 M0 Mp1],0:2*scheme_radius,length(r),m); M(1:2,1:2) = [c(1)/2 + c(2)/2 -c(1)/2 - c(2)/2; -c(1)/2 - c(2)/2 c(1)/2 + c(2) + c(3)/2;]; M(m-1:m,m-1:m) = [c(m-2)/2 + c(m-1) + c(m)/2 -c(m-1)/2 - c(m)/2; -c(m-1)/2 - c(m)/2 c(m-1)/2 + c(m)/2;]; M = 1/h*M; D2 = HI*(-M - c(1)*e_l*d1_l' + c(m)*e_r*d1_r'); end D2 = @D2_fun; % Fourth derivative, 0th order accurate at first 6 boundary points stencil = [1, -4, 6, -4, 1]; diags = -2:2; M4 = stripeMatrix(stencil, diags, m); M4_U = [ 0.13e2/0.10e2 -0.12e2/0.5e1 0.9e1/0.10e2 0.1e1/0.5e1; -0.12e2/0.5e1 0.26e2/0.5e1 -0.16e2/0.5e1 0.2e1/0.5e1; 0.9e1/0.10e2 -0.16e2/0.5e1 0.47e2/0.10e2 -0.17e2/0.5e1; 0.1e1/0.5e1 0.2e1/0.5e1 -0.17e2/0.5e1 0.29e2/0.5e1; ]; M4(1:4,1:4) = M4_U; M4(m-3:m,m-3:m) = rot90(M4_U, 2); M4 = 1/h^3*M4; D4=HI*(M4 - e_l*d3_l'+e_r*d3_r' + d1_l*d2_l'-d1_r*d2_r'); end