view +grid/bspline.m @ 774:66eb4a2bbb72 feature/grids

Remove default scaling of the system. The scaling doens't seem to help actual solutions. One example that fails in the flexural code. With large timesteps the solutions seems to blow up. One particular example is profilePresentation on the tdb_presentation_figures branch with k = 0.0005
author Jonatan Werpers <jonatan@werpers.com>
date Wed, 18 Jul 2018 15:42:52 -0700
parents 4f7930d2d2c4
children
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% Calculates a D dimensional p-order bspline at t with knots T and control points P.
%  T = [t0 t1 t2 ... tm] is a 1 x (m+1) vector with non-decresing elements and t0 = 0 tm = 1.
%  P = [P0 P1 P2 ... Pn] is a D x (n+1) matrix.

% knots p+1 to m-p-1 are the internal knots

% Implemented from: http://mathworld.wolfram.com/B-Spline.html
function C = bspline(t,p,P,T)
    m = length(T) - 1;
    n = size(P,2) - 1;
    D = size(P,1);

    assert(p == m - n - 1);

    C = zeros(D,length(t));

    for i = 0:n
        for k = 1:D
            C(k,:) = C(k,:) + P(k,1+i)*B(i,p,t,T);
        end
    end

    % Curve not defined for t = 1 ? Ugly fix:
    I = find(t == 1);
    C(:,I) = repmat(P(:,end),[1,length(I)]);
end

function o = B(i, j, t, T)
    if j == 0
        o = T(1+i) <= t & t < T(1+i+1);
        return
    end

    if T(1+i+j)-T(1+i) ~= 0
        a = (t-T(1+i))/(T(1+i+j)-T(1+i));
    else
        a = t*0;
    end

    if T(1+i+j+1)-T(1+i+1) ~= 0
        b = (T(1+i+j+1)-t)/(T(1+i+j+1)-T(1+i+1));
    else
        b = t*0;
    end

    o = a.*B(i, j-1, t, T) + b.*B(i+1, j-1, t, T);
end